WebJun 23, 2024 · Your argument is sufficient to show the dot operator is well-defined. My guess is that they meant to ask a different question. The hint is that they use G for the set, which suggests they may be thinking of groups. I think they meant to specify that where those two elements are considered as Abelian groups under addition. WebJul 7, 2024 · Therefore, f − 1 is a well-defined function. If a function f is defined by a computational rule, then the input value x and the output value y are related by the equation y = f(x). In an inverse function, the role of the input and output are switched. Therefore, we can find the inverse function f − 1 by following these steps:
How to show that a function is well-defined - Quora
WebApr 21, 2010 · Apr 20, 2010. #1. Hi. I am trying to show that for f belonging to L^2 (-pi;pi) the integral that defines the complex Fourier Coefficients is well defined. In other words what I need to show is that. int_from -pi to pi ( f (x)*exp (-i*k*x) dx) < infinity (limited) I was thinking that since f belongs to L^2 (-pi;pi) then the integral of this will ... WebMar 24, 2014 · When defining a sequence x n = g ( x n − 1) (for some function g) and asking to show that { x n } is well-defined (since there is a root or a fraction somewhere in the definition), students often show that the sequence converges to something (under the assumption that it is well-defined) and do not see that they have to ensure that there is … seatech mumbai
How do I prove that a function is well defined?
WebAug 1, 2024 · So in general, to check well-definition, you need to write down an object and an arbitrary name for it, and make sure that the particular name doesn't change the result of … WebTo show that f is a function, we need to show that it is well-defined and has domain Z6. View the full answer. Step 2/2. Final answer. Previous question Next question. This problem has been solved! You'll get a detailed solution from a … WebWhen we write $f\\colon X\\to Y$ we say three things: $f\\subseteq X\\times Y$. The domain of $f$ is $X$. Whenever $\\langle x, y_1\\rangle, \\langle x, y_2\\rangle\\in sea technology s.r.l